10 ! full answer in step by step

It is convenient to start by understanding what the curve looks like in the region of interest. A graph can help. The limits of the sum will be from x=0 to x=3. We want each area in the sum to have the same width, so that width will be 3/3 = 1. That is, the area of each of the summands will be its height multiplied by 1, its width. In short, we can obtain the required sum by simply adding the height of the function at the appropriate points. Note that this process is eased immensely by having a table of values of the function.

a) The left end of each interval is where x ∈ {0, 1, 2}. The area is then
  f(0) +f(1) +f(2) = 3 + 4 + 3 = 10

b) The right end of each interval is where x ∈ {1, 2, 3}. The area is then
  f(1) +f(2) +f(3) = 4 + 3 + 0 = 7

c) The middle of each interval is where x ∈ {0.5, 1.5, 2.5}. The area is then
  f(0.5) +f(1.5) +f(2.5) = 3.75 + 3.75 + 1.75 = 9.25

d) The trapezoidal rule averages the left and right ends of each interval. We can obtain the same result by averaging the Left Sum and the Right Sum.
  (10 + 7)/2 = 8.5

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For comparison, the actual area under the curve in the first quadrant is 9.00.

Left Sum
If n = 3, then the first rectangle goes from 0 to 1 on the x axis. The y axis (if you are using a left sum) is on 3. 
Area = 1 * 3 + 1*3 (the second rectangle is the same as the first).  + 1 * 3 again.

Area = 9

Right Sum
The right side of the rectangle on the left (read that carefully if you dare) intersects the curve at (1, 4) so the area = 4.

The second rectangle in the middle with give you  y = 3 + 2*x - x^2 The third rectangle is 3 + 2*2 - 4  = 3. So the second rectangle = 3*(2-1) = 3

The third rectangle  =  3 * 0 = 0

The total area = 4 + 3 = 7

Mid rectangle. 
The x values are 1/2, 1 1/2 and 2 1/2 You take 1/2 on either side of them so that the width of the rectangle is 1

f(1/2) = 3+ 2x - x^2
f(1/2) = 3.75

f(3/2) = 3 + 2*(3/2) - 2.25
f(3/2) = 3.75

f(2.5) = 2 + 5 - 6.25
f(2.5) =  0.75

The area  = 0.75 + 3.75 + 3.75
The area = 8.25

The D part is with trapezoids. You just need to take the left and right values for b1 and b2. for 3 trapezoids. I leave this part for you.

The mode is the most frequently occurring value.