Identify domain & range expand each log

The domain of a function is all the "allowed" x values.  Here, that side to side movement, or domain, of the function is found within the set of parenthesis with the x.  The number outside the parenthesis, the -1 here, is up and down movement, or range.  So the format for the side to side movement in an expression, is (x-h), where h is the x coordinate of our starting point on this graph.  Since our side to side is (x+1), that would fit into our expression as (x-(-1)), so it moves 1 to the left of the original starting place, which is x = 0.  Therefore, the domain is .  Now for the expansion...when you have a quotient, you expand a log by subtracting the denominator from the numerator, like this, in your case: .  Depending upon how far you need to go with this, the simplification from above would be this: .  If you needed to solve that, it would start like this: .  In exponential form we would rewrite as .  Now take the log of both sides to bring down that x:  .  Following the properties of logs, we can bring down the x to get this: x log5 = log(15807).  Solving for x means we divide both sides by log5 to find that x = 6.00

Ais c multiple rthvjjbv

Y= -2x-1 the negative in front of the 2 is because the slope is negative and the -1 is because it’s down 1 on the y axis.