Mathematics, 17.07.2019 15:30 musicaljay8320
What are the zeros in the function f(x)= x^3+x^2-6x -3,0, and 2 -3,0, and 1 -1,0, and 3 -2,0, and 3
Answers: 1
![f(x)=x^3+x^2-6x\\\\text{The zeros:}\\\\f(x)=0\to x^3+x^2-6x=0\\\\x(x^2+x-6)=0\\\\x(x^2+3x-2x-6)=0\\\\x[x(x+3)-2(x+3)]=0\\\\x(x+3)(x-2)=0\iff x=0\ \vee\ x+3=0\ \vee\ x-2=0\\\\x=0\ \vee\ x=-3\ \vee\ x=2](/tpl/images/0100/6416/649e5.png)
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What are the zeros in the function f(x)= x^3+x^2-6x -3,0, and 2 -3,0, and 1 -1,0, and 3 -2,0, and 3...
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