Find the distance between the points (-3, 11) and (5, 5).

Formula for distance between two points:

d  = √((x₂-x₁)² + (y₂-y₁)²)

Let point 1 be (-3, 11) and point 2 be (5, 5)

Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.

d = √((x₂-x₁)² + (y₂-y₁)²)

   = √((5- -3)² + (5-11)²)

   = √((5+3)² + (5-11)²)

   = √((8)² + (-6)²)          8² = 8*8 = 64, (-6)² = -6*-6 = 36

   = √(64 + 36)

  = √(100)

  = 10

Distance = 10 units.

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