Bobby is playing a game where he flips a coin and rolls a number cube labeled 1 through 6. he listed the possible outcomes in the sample space shown below: {(h, 1), (h, 2), (h, 4), (h, 5), (h, 6), (t, 1), (t, 2), (t, 4), (t, 5), (t, 6)} which two elements did he leave out?

(H,3) and (T,3)

Step-by-step explanation:

We know that the sample space is a set of all possible outcomes of an experiment.

The given event : Bobby is playing a game where he flips a coin and rolls a number cube labeled 1 through 6.

Then the possible outcomes : {H,T}×{1,2,3,4,5,6}={(H, 1), (H, 2), (H,3), (H, 4), (H, 5), (H, 6), (T, 1), (T, 2), (T,3) (T, 4), (T, 5), (T, 6)}→ Sample space

When we compare it to the given sample space , the two elements he left out = (H,3) and (T,3)

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)