When a number is halfway between two multiples of ten, round to a. zero b. the smaller multiple c. the nearest five d. the larger multiple

D. The larger multiple

Step-by-step explanation:

When the number is halfway between two multiples of ten, its first(concerned) digit would be 5. For example, the number halfway between 10 and 100 is

The number halfway between 100 and 1000 is and so on..

In order to round 550 to nearest multiple of 10, we have to look for the digit at hundreds place. Since this digit in 550 is 5(the concerned 5 has been made bold), 550 will be rounded to the higher multiple, i.e. 1000

Similarly, 55 will be rounded to 100.

From here we can conclude that a number halfway between two multiples of ten will be rounded to the larger multiple of 10.

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

answer: i realy don't get it that much can you me figer it out pleas you

step-by-step explanation: