The ten students in a club are lined up in a row for a group photograph. how many different arrangements are possible if the club includes one set of identical triplets wearing matching clothes?

We know that

if the club includes one set of identical triplets wearing matching clothes

then

the number of different arrangements that are possible is

10! / 3! = (10*9*8*7*6*5*4*3!)/3!

=604,800

The answer is

604,800

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.

6 and 24

step-by-step explanation:

6 x 4 = 24