10 points if correct plus brainliest answer if right i will plz ! audrey has x pounds of red grapes and y pounds of green grapes. she has less than 5 pounds of grapes in all. which are reasonable solutions for this situation? check all that apply. (–1, 2) (1, 3.5) (2, 2) (4.5, 0.5) (5, 0)

(1, 3.5) and (2, 2)

Step-by-step explanation:

We have the inequality x+y < 5.

Checking each ordered pair:

For the first ordered pair, (-1, 2), we cannot have a negative number of grapes.  This solution is not reasonable.

For the second ordered pair, (1, 3.5),

1+3.5 = 4.5 < 5

This is a reasonable solution.

For the third ordered pair, (2, 2),

2+2 = 4 < 5

This is a reasonable solution.

For the fourth ordered pair, (4.5, 0.5),

4.5+0.5 = 5

This is not less than 5, so this is not a reasonable solution.

For the last ordered pair, (5, 0),

5+0 = 5

This is not less than 5, so this is not a reasonable solution.

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.