What is the equation of the line, in general from, that passes through the point (-1,-1) and is parallel to the line whose equation is x+y=3

So you have the find the slope of the line first, and the new line is have the same slope since they’re parallel. So to convert the equation to slope intercept form y=mx+b, the equation is now y=-x+3.
So the slope of new line is -1
Now plug in the point because the point is one the line.
-1=(-1)*(-1)+b
-1=1+b
2=b
So the new equation is y=-1x*2