Asmall class has 10 students. seven of the students are male and three are female. you write the name of each student on a small card. the cards are shuffled thoroughly and you choose one at random, observe the name of the student, and replace it in the set. the cards are thoroughly reshuffled and you again choose a card at random, observe the name, and replace it in the set. this is done a total of five times. let x be the number of cards observed in these four trials with a name corresponding to a male student. the random variable x has which probability distribution?

Given that the shuffling is done 5 times

So n=5

Also given that there are 7 male students and 3 female students

So total number of students = 10

Hence the probability of getting male student is selecting 7 male student from total 10 students.

Probability of selecting male student = 7 / 10 = 0.7

Therefore, its binomial distribution with parameters n=5 and p=0.7

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it