In this threaded discussion, you will draw on the data you developed to estimate the minimum and maximum signal delivery times between earth and mars. respond to the following online. share your estimates (in minutes) for the signal delivery times, and look at the estimates given by other students. include the following in your response: if other students have different estimates, work with each other to clarify the correct answers. why is the function relating distance from earth and signal delivery time a direct linear variation? what is the value of k? a complete exchange involves receiving a message and then sending a reply. what function equation relates distance from earth and signal delivery time for a complete exchange?

Given
2-way interplanetary (Earth–Mars) communication by electromagnetic radiation (radio)

Find
a) Why is the function relating distance to signal delivery time a direct linear variation?
b) What is the constant of variation (k)?
c) What function relates distance from Earth and round-trip signalling time?

Solution
a) For the purposes of this problem, we assume space is flat and that planetary velocities are well below the speed of light, so that speed, time, and distance are related by
  time = distance / speed
The relevant speed here is the speed of an electromagnetic signal, the speed of light.
The function is linear because we assume it is linear (that the non-linearities are negligible).

b) From part (a), for
  time = k*distance
the value of k is
  k = 1/c . . . . . where c = the speed of light

c) If the distance (d) from Earth to Mars does not change substantially during the flight time of the signal, the round-trip time (T) will be
  T = 2*(k*d)
  T = 2d/c


In fact, space is warped by the sun, planets, and other celestial bodies, and the distance from one planet to another is constantly changing. Thus, the signalling time is not a linear function of distance (even if we could state the distance), but is also a function of the path taken and the way that path is changing. Calculating these effects is way beyond the scope of this question, even if all the relevant data were known (which it is not).

40%=2/550=1/230=3/1056=14/25

0=6x+2y+10 is equivalent to the simplified form: y= -3x - 5• parallel lines always have the same slope, different y intercept knowing this, we can say the slope, or m of the line parallel to y= -3x - 5 is -3.m= -3 hope this could !