What is the equation of the line that is perpendicular to y = 2x – 4 and has a y-intercept of –2?

Hi there!

The equation of a line perpendicular to another line always has an opposite and reciprocal slope. For this equation here, the opposite and reciprocal slope of 2x is -1/2x. This is because 2 becomes negative (-2) and it is flipped from the numerator (-1/2). So, our equation so far is y = -1/2x + b. B represents the y-intercept. And since we already know the y-intercept, all we have to do is plug it in!
Here is our finished equation: y = -1/2x - 2.

Hope this helps!! :)

Answer: b 2 = 1.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

therefore, b 2= 1.