What is a zero of the quadratic function f(x)=4x^2+24+11?

The roots of this equation are x = -5.5 and x = -.5

We can find this by using the quadratic equation which is listed below.

Now in order to find the right numbers to put into this equation. we look back to the original problem. Our a value will always be the number attached to x^2 (in this case 4), the b value will be attached to x (24) and the c value will be attached to no variable (11). Now we can do the operations and solve.

-3 +/- 5/2

-3 + 5/2 = -0.5 and -3 - 5/2 = -5.5

Giving you those x values.

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