What is the area of a regular hexagon with a side length of 10 meters and a distance from the center to a vertex of 10 meters?

We know that
the area of a regular hexagon=(Perimeter*Apothem)/2

step 1
find the perimeter
P=6*b
where b is the side length
b=10 m
so
P=6*10> P=60 m

step 2

Find the apothem
Applying the Pythagorean Theorem

c²=a²+b²> a²=c²-b²
where
a is the apothem
b=10/2> 5 m
c=10 m
so
a²=10²-5²> a²=100-25> a=√75 m
apothem=√75 m

step 3
 find the area of a regular hexagon
the area of a regular hexagon=(Perimeter*Apothem)/2
the area of a regular hexagon=[60*√75]/2> 30√75 > 150√3 m²

the answer is
the area of a regular hexagon is 150√3 m²