The diagram shows corresponding lengths in two similar figures. find the ratio of the perimeters and the ratio of the areas. a. 3: 4 and 180: 240 b. 3: 4 and 9: 16 c. 9: 16 and 180: 240 d. 15: 20 and 180: 240

Remark
This question does have a trick in it. It is going to be very difficult to come up with a general solution for any quadrilateral. Because of your grade level, I think the question would be satisfied with any solution at all. That said, I think the easiest way to do this is to use a square. 

Solve the perimeter of a small square.
Let each side = 3
Then the perimeter = 4*3 
P = 12

Solve the Perimeter of the larger square
Let each side = 4
Then the Perimeter = 4*4 
P = 16

What is the ratio of the perimeters of both squares?
P_small / P_ large = 12 / 16 = 3/4 
That means that the perimeters are in the ratio of the given conditions. 

Note
15/20 is the same thing as 3/4.

Second condition.
Find the area of both squares.

Small square = s^2
A_small_square = 3 * 3 = 9

Area Large Square = 4*4
Area of the Large Square = 16
Ratio of the Areas = A_s/A_L = 9 / 16

Answer
B <<<<< Answer

Logical equivalent of the give question is its contrapositive