What is the equation of a line that is perpendicular to y=3x-2 and passesbthrough the point (6,8) a. y=1/3x+10 b. y=1/3x+6 c. y= -1/3x+4 d. y=-1/3x+8

The answer is A

Step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18