Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
a(n)=-6+(n-1)(6)
a. 0, 18, 54
b. –6, 18, 54
c. 6, 18, 54
d. –6, 12, 48

The firs term
A(1)=-6+(1-1)(6)
A(1)=-6+(0)(6)
A(1)=-6

The fourh term
A(n)=-6+(n-1)(6)
A(4)=-6+(4-1)(6)
A(4)=-6+(3)(6)
A(4)=-6+18
A(4)=12

The tenth term
A(10)=-6+(10-1)(6)
A(10)=-6+(9)(6)
A(10)=-6+54
A(10)=48

 
D.  -6,12,48