The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 14 units. what is bc, the height of the pyramid?

The picture in the attached figure

we know that
The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 14 units
so
AC=CD=AD=14 units

in the right triangle ABC
tan A=opposite side angle A/adjacent side angle A
opposite side angle A=BC
adjacent side angle A=AC
angle A=45 degrees
so
tan 45=BC/14------------> BC=14*tan 45-------> BC=14*1-----> BC=14 units

the answer is
the height of the pyramid is 14 units (BC)

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!