Astudent performed the following steps to find the solution to the equation x^2 +14x +40 = 0. where did the student go wrong? step 1. factor the polynomial into (x + 4) and (x + 10) step 2. x + 4 = 0 and x + 10 = 0 step 3. x = -4 and x = 10

The student went wrong in Step 3.

After setting each factor equal to 0, the student solved for x wrong in the second equation. To solve for x in the second equation, the student should subtract 10 from both sides. The solutions of the equation would be X = -4 and X = -10.

X + 10 = 0
X + 10 -10 = 0 - 10
X = -10

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.