Solve.
5y - 10 = -25

pls explain

5y-10=-25
5y=-25+10 addition property of equa
5y=-15 simplifying
Y=-15/5 dividing property
Y=-3

5y-10=-25 
Move constant to the right by adding its opposite to both sides
5y-10+10=-25+10
Eliminate the opposites
5y=-25+10

-25+10
Keep the sign of the number with the lager absolute value and subtract the smaller absolute value from the larger
-(25-10)
Subtract the nubers
-15
5y=-15
Divide both sides of the equation by 5
5y/5=-15/5
any expression divided by itself equals 1
y=-15/5
calculate the quatient
y=-3