Line jk passes through points j(–3, 11) and k(1, –3). what is the equation of line jk in standard form?

Hello!

First of all we find the slope by dividing the difference of the y values by the difference of the x values as seen below.



The slope of our line is 7/2, or 3.5
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Now we will put the slope and a point on our line into slope intercept form and solve for b. We will use (-3,11).

11=3.5(-3)+b
11=10.5+b
b=0.5

Our final equation is shown below.

y=3.5x+0.5

I hope this helps!