What are the factors of a polynomial with the following zeroes: -1, ⅔, 2 ? a (x-1)(x+⅔)(x-2) b (x-1)(3x-2)(x-2) c (x+1)(x-⅔)(x+2) d (x+1)(3x-2)(x-2)

When a zero of a polynomial is "c", a factor is (x - c).
If the zero is p/q, a factor will be (x - p/q) or (qx - p).

The appropriate choice here is
  d (x+1)(3x-2)(x-2)

9/12 is the answer because 3/4 times 3 each is 9/12

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