Timothy has a fenced-in garden in the shape of a rhombus. the length of the longer diagonal is 24 feet, and the length of the shorter diagonal is 18 feet. what is the length of one side of the fenced-in garden? 12 ft 15 ft 21 ft 108 ft

15 feet is the length of one side of the fenced-in garden.

Step-by-step explanation:

Diagonals of rhombus bisect each at 90 degree angle.

In rhombus ABCD

OA = OC =

OB = OD =

Since, the diagonal intersect at 90 degree angle.

Applying Pythagoras theorem in  ΔAOB

AB = 15 feet = Length of side of the rhombus fenced garden

15 feet is the length of one side of the fenced-in garden.

the red lines denote the population of the bacteria after 35 hours. that would be 2,409.24. the y-intercept is the blue line which is 800 because that is the starting point. the equation used to make the graph is 800(1.032)^h, where h is the number of hours.

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3