Given: aas triangle, a=23°, b=48°, a=14cm. find c, b, and c 109; 26.63cm; 33.88cm 109; 21.48cm; 40.11cm 19; 26.63cm; 33.88cm 19; 21.48cm; 40.11cm

The sum of the angles of a triangle is equal to 180 degrees.

We have then:

From here, we clear C:

Substituting values:

We now look for the lontigudes of the sides.

To do this, using the sines law we have:

From here, we clear c:

We repeat the same procedure for b:

The values of C, b and c are given by:

109; 26.63cm; 33.88cm

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

d? maybe

step-by-step explanation: