Mariana averaged 72 on her first three history exams. the first score was 78. the second score was 6 less than the third score. what did she score on the second and third exams?

Okay, let's assign variables:
second exam: a
third exam: b
Because the second score is 6 less than the third, we know that
a = b - 6
knowing this, the numbers now become:
second exam: b - 6
third exam: b
now that we have these numbers. We have to find the average by  adding all the numbers and dividing:
(72 + b + b - 6) / 3 = 78
(72 + 2b - 6) / 3 = 78
(2b + 66) / 3 = 78
To get rid of the 3, we multiply both sides by 3:
2b + 66 = 234
2b = 168
b = 84
Mariana scored 84 points on her third exam and 78 on her second exam.

Idon't know that language

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