Asquirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. if the squirrel's centripetal acceleration is 0.43 m/s 2 , what is the radius of the circle? 0.60 m 1.2 m 0.36 m 0.84 m

Radius of the circle, r = 0.60 meters.

Step-by-step explanation:

It is given that,

Speed of the squirrel, v = 0.51 m/s

The centripetal acceleration of the squirrel,

We need to find the radius of the circle. The centripetal acceleration is given by :

r = 0.60 m

So, the radius of the circle is 0.60 meters. Hence, this is the required solution.

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.