How do you write y=3/7x-1 in standard form

The expression in standard form is 7y - 3x  = -7

The standard form of the equation of a line is expressed as Ax + By = C

m is the slope of the line

b is the y-intercept

Given the expression y = 3/7x - 1

Multiply through by 7

7y = 3x - 7

Subtract 3x from both sides

7y - 3x = -7

Hence the expression in standard form is 7y - 3x  = -7

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δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)