Triangle pqr is transformed to triangle p'q'r'. triangle pqr has vertices p(4, 0), q(0, −4), and r(−8, −4). triangle p'q'r' has vertices p'(1, 0), q'(0, −1), and r'(−2, −1). plot triangles pqr and p'q'r' on your own coordinate grid. part a: what is the scale factor of the dilation that transforms triangle pqr to triangle p'q'r'? explain your answer. (4 points) part b: write the coordinates of triangle p"q"r" obtained after p'q'r' is reflected about the y-axis. (4 points) part c: are the two triangles pqr and p''q''r'' congruent? explain your answer. (2 points)

PART A: The scale factor of dilation is 1/4 as you are dividing the vertices by 4 the get the new image.

PART B: P"(-1,0) Q"(0,-1) R"(2,-1)when reflecting over the y-axis change the x-coordinate by making it either positive/negative (opposite).

PART C: The two triangles are not congruent as they are the same shape, but not the same size (definition of being congruent). Hope this helped :))

  21.3

step-by-step explanation:

multiplying the given equation by c/sin(25°), we get

  c = 9/sin(25°) ≈ 21.2958 ≈ 21.3

we assume "c" is the length of ab, the side opposite angle c in triangle abc.

i will pick c put check it over to be sure

step-by-step explanation: