Radio signals travel at a rate of 3 × 10^8 meters per second. how many seconds would it take for a radio signal to travel from a satellite to the surface of the earth if the satellite is orbiting at a height of 7.5 × 10^6 meters?

This question is an example of d = r * t

r = rate

r = 3*10^8 m/s

t = ??

d = 7.5 * 10^6 meters.

Sub and solve

d = r * t

7.5 * 10^6 = 3 * 10^8 * t Divide both sides by 3 * 10^8

7.5 * 10^6 / (3 * 10^8) = t

2.5 * 10^(6 - 8) = t

2.5 * 10^-2 seconds = t or

0.025 seconds = t

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: