Let g(x) = 4x − 4 + |x + 6|. find all values of a which satisfy the equation g(a) = 3a + 2. (enter your answers as a comma-separated list. if an answer does not exist, enter dne.)

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let 'z' common variable for g(x) and g(a).

Then 4z-4+|z+6|=3z+2; ⇔ z-6+|z+6|=0; ⇔ z∈(-oo;-6)∩{0}.

All the additional details are in the attachment.

(-oo;-6)∩{0}

a

step-by-step explanation: