If the radius of a cylinder was shrunk down to a quarter of its orignal size and the height was reduced to a third of its original size, what would be the formula to find the modified surface area?

Surface area, S, is

Replace the radius with (1/4)r and the height with (1/3)h and you get the new surface area

Step-by-step explanation:

Let h be the original height of cylinder and r be the original radius of cylinder

According to question

Surface area of cylinder=

Using the formula

Surface area of cylinder=

Surface area of cylinder=

if x decreases by 4 then y increases by 10

step-by-step explanation:

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.