What is tan(-7pi) in simpliest radical form? what is csc(-3pi/4) in simpliest radical form?

check the picture below on the left-side.

so, negative angles move "clockwise", namely how the hands on a clock move, so -7π, is really -2π-2π-2π-π, which means, we go around the circle clockwise 3 times, as you see there in the green lines, and then we go a little bit more, namely -π, and that lands us on the -7π, or -π or the positive counterpart of π angle, same terminal point for all three.

and since tan(π) = 0, then tan(-7π) = 0, and likewise tan(-π) =0.

check the picture below on the right-side.

as you see there, the -3π/4 angle, will land there, namely is the same terminal point as the 5π/4 positive counterpart.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

$5.41

step-by-step explanation:

$20 - $14.51 = $5.49.