Arectangular field is 95 yards long and 50 yards wide what is the length and width of another rectangular field that has the same perimeter but a larger area

the answer can vary, but I got 80 by 65

step by step explanation: to find perimeter its adding all the sides up, so 95×2+50×2= 290 and area is multiplying so I would be 95×50= 4,750

so 80×2+65×2= 290 also

and 80×65 is 5,200 and 5,200 > 4,750 so

the total answer is 80 by 65

y > 1/3x

y < = -x + 4

hope this : )

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