Me . in △abc, m∠a=23 △ a b c , m ∠ a = 23 °, a=12 a = 12 , and b=15 b = 15 . find c c to the nearest tenth. a. 24.3 b. 14.4 c. 19.5 d. 26.5

we know that

Step 1

Find B

Applying the law of sines

a /sinA=b /sin B> solve for sin B

sin B=(b/a)*sin A> sin B=(15/12)*sin 23> sin B=0.4884

B=arc sin(0.4884)> B=29.2°

Step 2

Find C

we know that

A+B+C=180°

C=180-(23+29.2)> C=127.8°

Step 3

Find c

a /sinA=c /sin C> solve for c

c=a*sin C/sin A> c=12*sin 127.8/sin 23>c=24.3 units

the answer is

24.3

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

the answer is c just got it on ed

step-by-step explanation: