[will mark as brainliest] what is the inverse of the function below? f(x) = 2^x + 6 a.) f^-1(x) = 6 + log2x b.) f^-1(x) = log2(x + 6) c.) f^-1(x) = 6log2x d.) f^-1(x) = log2(x - 6)

What is the inverse of the function below?

f(x) = 2^x + 6

1) Replace "f(x)" with "y" y = 2^x + 6

2) Interchange x and y: x=2^y + 6

3) Solve this for y: 2^y = x - 6 Take the log to the base 2 of both sides:

y = (log to the base 2 of) (x-6)

4) replace y with

-1

f (x)

We obtain:

-1

f (x) = (log to the base 2 of) (x-6)

step-by-step explanation: