If x2 + y2 = 100 and dy/dt = 3, find dx/dt when y = 8. (enter your answers as a comma-separated list.)

Answer;

dy/dx = - or + 4 and y = 8

Explanation;

x² + y² = 100

when y = 8

Then, x² + 8² = 100

thus; x² = 100 - 64 = 36

x² = 36

therefore; x = + 6 or -6

2x (dx/dt) + 2y (dy/dt) = 0

x(dx/dt) + y (dy/dt) =0

When dy/dt = 3

= (- or + 6) dx/dt + 8 (3) = 0

thus; dx/dt = - 8 (3/6)

= + or - 4.

Answer; y = 8 and dx/dy = - or + 4

x=30

step-by-step explanation:

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: