Using the quadratic formula to solve 4x^2-3x+9=2x+1, what are the values of x?

Rewrite 4x^2-3x+9=2x+1 as 4x^2-5x+8 = 0

Here, a = 4, b = -5 and c = 8. Then,

5 plus or minus sqrt (25 -4(4)(8) )

x =

8

5 plus or minus sqrt (-103)

=

8

5 plus or minus i*sqrt(103)

Then x =

8

=

8

=

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2