Asap pls a particle is moving along a projectile path where the initial height is 160 feet with an initial speed of 144 feet per second. what is the maximum height of the particle? hint: use h(t) = -16t2 + vt + s. 128 feet 224 feet 272 feet 484 feet

Assuming Earth's gravity, the formula for the flight of the particle is: 

s(t) = -16t^2 + vt + s = -16t^2 + 144t + 160. 

This has a maximum when t = -b/(2a) = -144/[2(-16)] = -144/(-32) = 9/2. 

Therefore, the maximum height is s(9/2) = -16(9/2)^2 + 144(9/2) + 160 = 484 feet. 

484

Step-by-step explanation:

test=right

slope is 35 and 20 miles is the y-intercept.

step-by-step explanation: