If c varies directly as d-3, and if c=16 when d=7, find c when d=10

Given, c varies directly as d-3. So, the equation will be:

c= k(d-3) where k is constant of variation.

If c=16 when d=7. So, plug in these values in the above equation. Hence,

16=k (7-3)

16=k*4

16/4= k

k= 4

Now plug in k=4 in the above equation to get the equation of this variation.

c=4(d-3).

We need to find c when d=10. So, plug in d=10 in the above equation to get the value of c. So,

c =4(10-3)

=4*7

=28

So, c=28.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.