If you are dealt 55 cards from a shuffled deck of 52 cards, find the probability of getting threethree queensqueens and twotwo kingskings.

We need to find the probability of getting 3 queens and 2 kings

In 52 cards, we have 4 queens and 4 kings

We need to select 3 queens from 4 queens

\[\frac{n!}{r!(n-r)!}\]

So different combinations of selecting 3 queens from 4 queens is 4C3

\[\frac{4!}{3!(4-3)!}\] = 4

We need to select 2 kings from 4 kings

\[\frac{n!}{r!(n-r)!}\]

So different combinations of selecting 2 kings from 4 kings is 4C2

\[\frac{4!}{2!(4-2)!}\] = 6

Total combination of selecting 5 cards from 52 cards = 52C5

\[\frac{52!}{5!(52-5)!}\] = 2598960

Probability of getting 3 queens and 2 kings = 4C3 * 4C2 / 5C52

\[\frac{4*6}{2598960}\]

1/ 108290

the answer would be a 24

step-by-step explanation:

c=2πr=2·π·3=24