Asystem of equations is shown below: x + 3y = 5 (equation 1) 7x − 8y = 6 (equation 2) a student wants to prove that if equation 2 is kept unchanged and equation 1 is replaced with the sum of equation 1 and a multiple of equation 2, the solution to the new system of equations is the same as the solution to the original system of equations. if equation 2 is multiplied by 1, which of the following steps should the student use for the proof? show that the solution to the system of equations 3x + y = 5 and 8x −7y = 6 is the same as the solution to the given system of equations show that the solution to the system of equations 8x − 5y = 11 and 7x − 8y = 6 is the same as the solution to the given system of equations show that the solution to the system of equations 15x + 13y = 17 and 7x − 8y = 6 is the same as the solution to the given system of equations show that the solution to the system of equations −13x + 15y = 17 and 7x − 8y = 6 is the same as the solution to the given system of equations

8x − 5y = 11 and 7x − 8y = 6

Step-by-step explanation:

I took the test and got it right.

First Let we solve the Original system of equations:

equation (1):

equation (2):

Multiplying equation (1) by 7, we get

Subtracting,

implies

Then

Thus the solution of the original equation is

Now Let we form the new equation:

Equation 2 is kept unchanged:

Equation (2):

Equation 1 is replaced with the sum of equation 1 and a multiple of equation 2:

Equation (1):

Now solve this two equations:

Multiply (1) by 7 and (2) by 8,

Subtracting, implies

Then x=2.

so the solution for the new system of equation is x=2, y=1.

This Show that the solution to the system of equations 8x − 5y = 11 and 7x − 8y = 6 is the same as the solution to the given system of equations

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: