Find the equation of a line passing through the points (-3,6) and (1,2)

Hello!

First of all, we need to find the slope of our line. To do so we divide the difference in the y-values by the difference in the x-values as shown below.

=-1

Therefore, our slope is -1.

Now we plug our slope and a point from our line (1,2) into the slope intercept equation and solve for b.

2=-1(1)+b

2=-1+b

b=3

Now we have our final equation below.

y=-x+3

I hope this helps!

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