Abag contains one red pen, four black pens, and three blue pens. two pens are randomly chosen from the bag and are not replaced. to the nearest hundredth, what is the probability that a black pen is chosen first and then another black pen is chosen? 0.020.190.210.25

one+four+three=eight pens.

Two pens are selected without replacement.

Need probability of selecting two black pens.

Probability of selecting first black pen is four out of eight, 4/8

Probability of selecting second black pen is three remaining black pens out of the remaining 7 pens = 3/7

Probability of both events happening is the product of the two probabilities, according to the multiplication rule.

Therefore probability of selecting two black pens out of the initial eight pens

=(4/8)(3/7)=3/14=0.2143 (to the ten-thousandth).

Rounding to the hundredth will give you the required answer.

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2

x is the total time in minutes for the free response

you are given number of questions as 15 - m and time per item as 8 minutes

to find x multiply the two givens together:

x = 8 * (15-m) = 8(15-m)