provide the reasons for the proof. given: rumh is a rhombus. rubm is a rhombus. prove: rhm = umb

Here, RUMH and RUBM are two rhombus as shown in the diagram.

As, a rhombus has four equal sides,

so for RUMH, side RH = side HM = side MU = side UR

and for RUBM, side RM = side MB = side BU = side UR

As HM=UR and MB= UR , so we can write HM = MB

Now for two triangles ΔRHM and ΔUMB,

side RH = side MU

side RM = side BU

and side HM = side MB

'Side Side Side' theorem states that if three sides of one triangle are equal to three sides of another triangle respectively, then the two triangles are similar.

That means, ΔRHM = ΔUMB

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

image result for what is another name for consecutive interior angles? ​

when two lines are crossed by another line (called the transversal): the pairs of angles on one side of the transversal but inside the two lines are called consecutive interior angles. in this example, these are consecutive interior angles: d and f.

step-by-step explanation: