The equation of a circle is x2 + y2 + cx + dy + e = 0. if the radius of the circle is decreased without changing the coordinates of the center point, how are the coefficients c, d, and e affected? a. c, d, and e are unchanged. b. c increases, but d and e are unchanged. c. c and d decrease, but e is unchanged. d. c, d, and e increase. e. c and d are unchanged, but e decreases.

The equation of a circle is x2 + y2 + Cx + Dy + E = 0

The radius of the circle is decreased without changing the coordinates of the centre point.

Now we know that general equation of a circle is x^2 + y^2 +2gx +2fy +c

Here C=2g and D =2f and we know that -g and -f are co-ordinates of centre point which remains unchanged

So here in the given problem C and D are unchanged .

But we know that radius of a circle = √(g^2 + f^2 -c)

Here c is E and we are given that radius is decreased which is only possible when value of c i.e. E gets increased.

So correct answer is value of C and D remains unchanged but value of E is increased.

the formula of a slope:

we have the points (-2, 7) and (2, 3). substitute:

6x = 48

i hope this . 6 cards each and a total of $48. dvide each side by 6 and you will have your answer.