Consider the diagram and the paragraph proof below. given: right △abc as shown where cd is an altitude of the triangle prove: a2 + b2 = c2 because △abc and △cbd both have a right angle, and the same angle b is in both triangles, the triangles must be similar by aa. likewise, △abc and △acd both have a right angle, and the same angle a is in both triangles, so they also must be similar by aa. the proportions and are true because they are ratios of corresponding parts of similar triangles. the two proportions can be rewritten as a2 = cf and b2 = ce. adding b2 to both sides of first equation, a2 = cf, results in the equation a2 + b2 = cf + b2. because b2 and ce are equal, ce can be substituted into the right side of the equation for b2, resulting in the equation a2 + b2 = cf + ce. applying the converse of the distributive property results in the equation a2 + b2 = c(f + e). which is the last sentence of the proof? because f + e = 1, a2 + b2 = c2. because f + e = c, a2 + b2 = c2. because a2 + b2 = c2, f + e = c. because a2 + b2 = c2, f + e = 1.

Given: Right △ABC as shown where CD is an altitude of the triangle. We prove that a^2+b^2=c^2

Because △ABC and △CBD both have a right angle, and the same angle B is in both triangles, the triangles must be similar by AA.

Likewise, △ABC and △ACD both have a right angle, and the same angle A is in both triangles, so they also must be similar by AA.

The proportions c\a and a\f are true because they are ratios of corresponding parts of similar triangles.

The two proportions can be rewritten as a^2=cf and b^2=ce

Adding b^2 to both sides of first equation, a^2=cf , results in the equation a^2 + b^2 = cf+ b^2 .

Because b^2 and ce are equal, ce can be substituted into the right side of the equation for b^2 , resulting in the equation a^2 + b^2 = cf + ce .

Applying the converse of the distributive property results in the equation .

a^2 + b^2 = c (f + e)

The last sentence of the proof is

Because f + e = c, a^2 + b^2 = c^2 .

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation: