Find the measure of each angle. supplementary angles with measure (2x+4) and (3x+1) answers: a) 54 and 126 b) 74 and 106 c) 63 and 117 d) 64 and 116

Answer

74 AND 106

Explanation

Supplementary angles are those angles that add up to 180.

So, if (2x+4) and (3x+1) are supplementary angles they add up to 180.

(2x+4) + (3x+1) = 180

2x+4+3x+1=180

5x = 180 -5

5x + 175

x = 35

(2x+4) = 2×35 +4

=70+4

= 74

(3x+1) = 3×35 + 1

= 105 +1

= 106

its not b

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2