The graph of the quadratic $y = ax^2 + bx + c$ is a parabola that passes through the points $(-1,7)$, $(5,7)$, and $(6,10)$. what is the $x$-coordinate of the vertex of the parabola?

Two of the given points have the same y-value. The midpoint of those two will be on the line of symmetry, as is the vertex. The x-value there is (-1+5)/2 = 2.

Step-by-step explanation:

Let consider the following linear equation systems by using the known points and second-grade polynomial:

(-1, 7)

(5, 7)

(6,10)

After some algebraic manipulation, the values for the polynomial coefficients are found:

, ,

The polynomial is:

Lastly, the vertex is found by further handling:

The coordinates for the vertex are:

coin flip

non-answer:

choosing

sorry if this isnt what you're looking for i dont really understand the question

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer