Tyrell is going to be use asa to prove that pqr=sqr

Presumably our goal is to show PRQ=SRQ, PQR=SQR and QR=QR for ASA.

A. QR=QR is the reflexive property; things are congruent to themselves, TRUE

B. We need to prove that, but it doesn't have anything to do with the symmetric property.

C. PQ=SQ isn't something we'd need to show for our ASA proof

D. Again, not the symmetric property.

A

A. Prove that QR≅QR by the reflexive property.

Step-by-step explanation:

ASA postulate says that if two angles and the included side of a triangle are congruent to two angles and the included side of other triangle then the triangles are said to be congruent.  

In the given triangles ΔPQR and ΔSQR

∠PQR ≅∠SQR     {given}

∠QRP ≅ ∠QRS     {given}

In the figure , the included side of ∠PQR and ∠QRP= QR

The included side of ∠SQR  and ∠QRS =OR

So we need to probe QR≅QR by Reflexive property, to prove triangles ΔPQR and ΔSQR are congruent.

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

answer

a,b, and d

explanation

a reflection angle is more than

but less than;

an angle that measures

is a reflex angle.(true)

an angle that measures less than

is acute.(true)

provided we are considering angles greater or equal to zero.

an acute angle lies in the range.

an obtuse angle is less than 180° but more than 90°

an angle that measures 300° is obtuse (false)

an angle that measures 65° is an acute angle.(true)