If a rectangle has a length =p and a width =p+4, what is the area of the rectangle. what is the perimeter?

The area of a rectangle can be found by multiplying the length times the width, or A = l * w. The perimeter of the rectangle can be found by adding together the length twice and the width twice. From the given information, we know that l = p and w = p + 4, where l represents the length of the rectangle and w represents the width of the rectangle.

A = l * w = p(p+4) = p^2 + 4p

P = 2l + 2w = 2(p) + 2(p+4) = 2p + 2p + 8 = 4p + 8

Therefore, the area of the rectangle is p^2 + 4p and the perimeter of the rectangle is 4p + 8.

Hope this helps!

12r - 8 - 12

you have to combine like terms. below i have bolded the like terms:

12r - 8 - 12

together it combines to:

12r - 20

hope this !